投稿

検索キーワード「dy dx x 2y 1 2x 4y」に一致する投稿を表示しています

70以上 x(x-1)dy/dx-(x-2)y=x^3(2x-1) 291128-Dx x 2 2y 2 dy 0

イメージ
😊😊 x² d²y/dx² 2x dy/dx 4y = x² —(1) This is 2nd order differential equation in Cauchy Euler form;Calculus Find dy/dx y^2=1/ (1x^2) y2 = 1 1 − x2 y 2 = 1 1 x 2 Differentiate both sides of the equation d dx (y2) = d dx ( 1 1−x2) d d x ( y 2) = d d x ( 1 1 x 2) Differentiate the left side of Let 2 x = d d x ( x 2) Substitute into equation x 2 d y d x d d x ( x 2) y = x 2 − 1 Apply the reverse product rule d d x ( x 2 y) = x 2 − 1 Integrate both sides with respect to x ∫ Ex 9 4 12 Find Particular Solution X X2 1 Dy Dx 1 Y 0 Dx x 2 2y 2 dy 0